Which expressions are equivalent to (b^(2))^((1)/(9)) ? Choose all answers that apply: (A) (b^(-(1)/(9)))^(2) (B) (b^((1)/(9)))^(2) (C) (b^((1)/(2)))^(9) (D) None of the above

Understand Exponent Properties: Understand the properties of exponents. When an exponent is raised to another exponent, you multiply the exponents. (b^(2))^((1)/(9)) = b^(2*(1/9)) = b^(2/9)Compare with Simplified Expression: Compare the given options with the simplified expression b^(2/9). Option A: (b^(-(1)/(9)))^(2) = b^(-1/9*2) = b^(-2/9), which is not equal to b^(2/9).Check Option A: Check option B. Option B: (b^((1)/(9)))^(2) = b^(1/9*2) = b^(2/9), which is equal to b^(2/9).Check Option B: Check option C. Option C: (b^((1)/(2)))^(9) = b^(1/2*9) = b^(9/2), which is not equal to b^(2/9).Check Option C: Determine the correct answers based on the calculations. Only option B is equivalent to b^(2/9).

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Which expressions are equivalent to (b^(2))^((1)/(9)) ?
Choose all answers that apply:
(A) (b^(-(1)/(9)))^(2)
(B) (b^((1)/(9)))^(2)
(C) (b^((1)/(2)))^(9)
(D) None of the above

Which expressions are equivalent to $(b^{2})^{\frac{1}{9}}$ ? $\newline$ Choose all answers that apply: $\newline$ $(A)$ $(b^{-\frac{1}{9}})^{2}$ $\newline$ $(B)$ $(b^{\frac{1}{9}})^{2}$ $\newline$ $(C)$ $(b^{\frac{1}{2}})^{9}$ $\newline$ $(D)$ None of the above

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Math Problems

Algebra 1

Multiplication with rational exponents

Full solution

Q. Which expressions are equivalent to

(b^{2})^{\frac{1}{9}}

\newline

Choose all answers that apply:

\newline

(A)

(b^{-\frac{1}{9}})^{2}

\newline

(B)

(b^{\frac{1}{9}})^{2}

\newline

(C)

(b^{\frac{1}{2}})^{9}

\newline

(D)

None of the above

Understand Exponent Properties: Understand the properties of exponents. $\newline$ When an exponent is raised to another exponent, you multiply the exponents. $\newline$ $(b^{2})^{(\frac{1}{9})} = b^{2*(\frac{1}{9})} = b^{\frac{2}{9}}$
Compare with Simplified Expression: Compare the given options with the simplified expression $b^{\frac{2}{9}}$ . Option A: $(b^{-(\frac{1}{9})})^{2} = b^{-\frac{1}{9}*2} = b^{-\frac{2}{9}}$ , which is not equal to $b^{\frac{2}{9}}$ .
Check Option A: Check option B. $\newline$ Option B: $(b^{(\frac{1}{9})})^{2} = b^{\frac{1}{9}*2} = b^{\frac{2}{9}}$ , which is equal to $b^{\frac{2}{9}}$ .
Check Option B: Check option C. $\newline$ Option C: $(b^{(\frac{1}{2})})^{9} = b^{\frac{1}{2}*9} = b^{\frac{9}{2}}$ , which is not equal to $b^{\frac{2}{9}}$ .
Check Option C: Determine the correct answers based on the calculations. $\newline$ Only option B is equivalent to $b^{\frac{2}{9}}$ .