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What value of zz is a solution to this equation?\newlinez+15=19z + 15 = 19\newlineChoices:\newline(A)z=4z = 4\newline(B)z=6z = 6

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Q. What value of zz is a solution to this equation?\newlinez+15=19z + 15 = 19\newlineChoices:\newline(A)z=4z = 4\newline(B)z=6z = 6
  1. Isolate zz: Step 11: Isolate zz in the equation z+15=19z + 15 = 19.\newlineTo find zz, subtract 1515 from both sides of the equation.\newlineCalculation: 19−15=419 - 15 = 4\newlinez=4z = 4

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