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What value of rr is a solution to this equation?\newliner−10=2r - 10 = 2\newlineChoices:\newline(A)r=10r = 10\newline(B)r=12r = 12

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Q. What value of rr is a solution to this equation?\newliner−10=2r - 10 = 2\newlineChoices:\newline(A)r=10r = 10\newline(B)r=12r = 12
  1. Isolate rr: Step 11: r−10=2r - 10 = 2\newlineTo isolate rr, we should add 1010 to both sides of the equation.\newlineCalculation: r=2+10r = 2 + 10
  2. Calculate r: Step 22: r=12r = 12\newlineNow, rr equals 1212. Let's check if this value satisfies the original equation.\newlineSubstitute rr with 1212 in the original equation: 12−10=212 - 10 = 2

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