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Let’s check out your problem:
What value of
b
b
b
is a solution to this equation?
\newline
15
+
b
=
27
15 + b = 27
15
+
b
=
27
\newline
Choices:
\newline
(A)
b
=
11
b = 11
b
=
11
\newline
(B)
b
=
12
b = 12
b
=
12
View step-by-step help
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Math Problems
Algebra 1
Which x satisfies an equation?
Full solution
Q.
What value of
b
b
b
is a solution to this equation?
\newline
15
+
b
=
27
15 + b = 27
15
+
b
=
27
\newline
Choices:
\newline
(A)
b
=
11
b = 11
b
=
11
\newline
(B)
b
=
12
b = 12
b
=
12
Subtract
15
15
15
:
Subtract
15
15
15
from both sides to isolate
b
b
b
;
15
+
b
−
15
=
27
−
15
15 + b - 15 = 27 - 15
15
+
b
−
15
=
27
−
15
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