Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

What is the volume of a sphere with a diameter of 
55.6m, rounded to the nearest tenth of a cubic meter?
Answer: 
m^(3)

What is the volume of a sphere with a diameter of 55.6 m 55.6 \mathrm{~m} , rounded to the nearest tenth of a cubic meter?\newlineAnswer: m3 \mathrm{m}^{3}

Full solution

Q. What is the volume of a sphere with a diameter of 55.6 m 55.6 \mathrm{~m} , rounded to the nearest tenth of a cubic meter?\newlineAnswer: m3 \mathrm{m}^{3}
  1. Identify Formula: Identify the formula to calculate the volume of a sphere.\newlineThe formula for the volume of a sphere is V=43πr3V = \frac{4}{3}\pi r^3, where rr is the radius of the sphere.
  2. Calculate Radius: Calculate the radius of the sphere.\newlineThe diameter of the sphere is given as 55.655.6 meters. The radius is half of the diameter, so r=diameter2=55.6m2=27.8mr = \frac{\text{diameter}}{2} = \frac{55.6m}{2} = 27.8m.
  3. Substitute into Formula: Substitute the radius into the volume formula. V=(43)π(27.8m)3V = \left(\frac{4}{3}\right)\pi(27.8\,\text{m})^3
  4. Calculate Volume: Calculate the volume using the radius value. V=(43)π(27.8m)3=(43)π(27.8m×27.8m×27.8m)=(43)π(21483.92m3)V = \left(\frac{4}{3}\right)\pi(27.8\,\text{m})^3 = \left(\frac{4}{3}\right)\pi(27.8\,\text{m} \times 27.8\,\text{m} \times 27.8\,\text{m}) = \left(\frac{4}{3}\right)\pi(21483.92\,\text{m}^3)
  5. Evaluate Expression: Evaluate the expression to find the volume.\newlineV=43π(21483.92m3)43×3.14159×21483.92m335804.8m3V = \frac{4}{3}\pi(21483.92m^3) \approx \frac{4}{3} \times 3.14159 \times 21483.92m^3 \approx 35804.8m^3
  6. Round Volume: Round the volume to the nearest tenth of a cubic meter. The volume of the sphere is approximately 35804.8m335804.8\,\text{m}^3, which is already rounded to the nearest tenth.

More problems from Convert between customary and metric systems