A real estate purveyor purchases a 60,000 square foot (ft2) warehouse and decides to turn it into a storage facility. The warehouse's width is exactly 32 of its length. What is the warehouse's width? Round your answer to the nearest foot.
Q. A real estate purveyor purchases a 60,000 square foot (ft2) warehouse and decides to turn it into a storage facility. The warehouse's width is exactly 32 of its length. What is the warehouse's width? Round your answer to the nearest foot.
Identify Relationship: Identify the relationship between the width and length of the warehouse.The width is (32) of the length. This means if we let L represent the length, then the width W can be represented as W=(32)L.
Set Up Equation: Set up the equation for the area of the warehouse using the relationship between width and length.The area A of the warehouse is given by A=L×W. We know the area is 60,000 square feet, so we can write the equation as 60,000=L×(32)L.
Solve for Area: Solve the equation for L2.To find L, we need to solve for L2 first. We can rewrite the equation as 60,000=(32)L2. Multiplying both sides by (23) gives us (23)×60,000=L2.
Calculate L2: Calculate L2. Now we calculate L2 by multiplying (3/2) by 60,000. L2=(3/2)∗60,000=90,000.
Solve for L: Solve for L.To find L, we take the square root of L2. L=90,000. L is approximately equal to 300 feet (since 90,000=300).
Calculate Width: Calculate the width W using the relationship W=32L. Now that we know L is approximately 300 feet, we can find W by multiplying 32 by L. W=32×300=200 feet.
Round Answer: Round the answer to the nearest foot. The calculated width W is 200 feet, which is already a whole number, so no rounding is necessary.
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