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What is the volume of a hemisphere with a diameter of 
57.6m, rounded to the nearest tenth of a cubic meter?
Answer: 
m^(3)

What is the volume of a hemisphere with a diameter of 57.6 m 57.6 \mathrm{~m} , rounded to the nearest tenth of a cubic meter?\newlineAnswer: m3 \mathrm{m}^{3}

Full solution

Q. What is the volume of a hemisphere with a diameter of 57.6 m 57.6 \mathrm{~m} , rounded to the nearest tenth of a cubic meter?\newlineAnswer: m3 \mathrm{m}^{3}
  1. Calculate Radius: To find the volume of a hemisphere, we first need to find the volume of a full sphere and then divide it by 22. The formula for the volume of a sphere is V=43πr3V = \frac{4}{3}\pi r^3, where rr is the radius of the sphere. Since the diameter of the sphere is given as 57.657.6 meters, the radius rr is half of the diameter.\newlineCalculation: r=diameter2=57.6m2=28.8mr = \frac{\text{diameter}}{2} = \frac{57.6\text{m}}{2} = 28.8\text{m}
  2. Substitute Radius in Formula: Now we can substitute the radius into the formula for the volume of a sphere.\newlineCalculation: Vsphere=43π(28.8m)3V_{\text{sphere}} = \frac{4}{3}\pi(28.8\,\text{m})^3
  3. Calculate Volume of Full Sphere: We calculate the volume of the full sphere using the radius we found.\newlineCalculation: Vsphere=43π(28.8m)3=43π(23832.832m3)43×3.14159×23832.832m3125663.706m3V_{\text{sphere}} = \frac{4}{3}\pi(28.8\,\text{m})^3 = \frac{4}{3}\pi(23832.832\,\text{m}^3) \approx \frac{4}{3} \times 3.14159 \times 23832.832\,\text{m}^3 \approx 125663.706\,\text{m}^3
  4. Divide Volume by 22: Since we want the volume of a hemisphere, we divide the volume of the sphere by 22.\newlineCalculation: Vhemisphere=Vsphere2125663.706m3262831.853m3V_{\text{hemisphere}} = \frac{V_{\text{sphere}}}{2} \approx \frac{125663.706\,\text{m}^3}{2} \approx 62831.853\,\text{m}^3
  5. Round Final Volume: Finally, we round the volume of the hemisphere to the nearest tenth of a cubic meter.\newlineCalculation: Vhemisphere62831.9m3V_{\text{hemisphere}} \approx 62831.9\,\text{m}^3

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