Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

What is the volume of a cylinder, in cubic 
ft, with a height of 
3ft and a base diameter of 
18ft ? Round to the nearest tenths place
Answer: 
V=◻ft^(3)

What is the volume of a cylinder, in cubic ft \mathrm{ft} , with a height of 3ft 3 \mathrm{ft} and a base diameter of 18ft 18 \mathrm{ft} ? Round to the nearest tenths place\newlineAnswer: V=ft3 V=\square \mathrm{ft}^{3}

Full solution

Q. What is the volume of a cylinder, in cubic ft \mathrm{ft} , with a height of 3ft 3 \mathrm{ft} and a base diameter of 18ft 18 \mathrm{ft} ? Round to the nearest tenths place\newlineAnswer: V=ft3 V=\square \mathrm{ft}^{3}
  1. Identify formula for volume: Identify the formula for the volume of a cylinder.\newlineThe formula for the volume of a cylinder is V=πr2hV = \pi r^2 h, where VV is the volume, rr is the radius of the base, and hh is the height of the cylinder.
  2. Calculate base radius: Calculate the radius of the base of the cylinder.\newlineThe diameter of the base is given as 18ft18\,\text{ft}. The radius is half of the diameter, so r=diameter/2=18ft/2=9ftr = \text{diameter} / 2 = 18\,\text{ft} / 2 = 9\,\text{ft}.
  3. Substitute values into formula: Substitute the values into the volume formula.\newlineUsing the radius from Step 22 and the given height of 33 ft, we substitute these values into the volume formula: V=π×(9 ft)2×3 ftV = \pi \times (9 \text{ ft})^2 \times 3 \text{ ft}.
  4. Calculate volume: Calculate the volume.\newlineV=π×81ft2×3ft=π×243ft3V = \pi \times 81 \, \text{ft}^2 \times 3 \, \text{ft} = \pi \times 243 \, \text{ft}^3.\newlineSince π\pi is approximately 3.141593.14159, we can calculate the volume as V3.14159×243ft3V \approx 3.14159 \times 243 \, \text{ft}^3.
  5. Perform multiplication: Perform the multiplication to find the volume. V3.14159×243ft3763.407ft3V \approx 3.14159 \times 243 \, \text{ft}^3 \approx 763.407 \, \text{ft}^3.
  6. Round volume: Round the volume to the nearest tenths place. Rounded to the nearest tenths place, the volume is approximately 763.4ft3763.4\,\text{ft}^3.

More problems from Convert between customary and metric systems