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What is the volume, in cubic 
ft, of a cylinder with a height of 
11ft and a base radius of 
2ft, to the nearest tenths place?
Answer: 
V=◻ft^(3)

What is the volume, in cubic ft \mathrm{ft} , of a cylinder with a height of 11ft 11 \mathrm{ft} and a base radius of 2ft 2 \mathrm{ft} , to the nearest tenths place?\newlineAnswer: V=ft3 V=\square \mathrm{ft}^{3}

Full solution

Q. What is the volume, in cubic ft \mathrm{ft} , of a cylinder with a height of 11ft 11 \mathrm{ft} and a base radius of 2ft 2 \mathrm{ft} , to the nearest tenths place?\newlineAnswer: V=ft3 V=\square \mathrm{ft}^{3}
  1. Formula for Volume: To find the volume of a cylinder, we use the formula V=πr2hV = \pi r^2 h, where VV is the volume, rr is the radius of the base, and hh is the height of the cylinder. We are given the radius r=2r = 2 ft and the height h=11h = 11 ft.
  2. Calculate Base Area: First, we calculate the area of the base (circle) using the formula A=πr2A = \pi r^2. Substituting the given radius r=2r = 2 ft, we get A=π(2)2=4πA = \pi(2)^2 = 4\pi square feet.
  3. Calculate Volume: Next, we calculate the volume by multiplying the area of the base by the height of the cylinder. So, V=4π×11ft=44πV = 4\pi \times 11 \, \text{ft} = 44\pi cubic feet.
  4. Round to Nearest Tenths: Finally, we need to round the result to the nearest tenths place. The value of π\pi is approximately 3.14163.1416. Therefore, V44×3.1416=138.2304V \approx 44 \times 3.1416 = 138.2304 cubic feet. Rounded to the nearest tenths place, the volume is approximately 138.2138.2 cubic feet.

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