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What is the value of AA when we rewrite 1.441.2x1.44^{-1.2 x} as AxA^{x} ?\newlineChoose 11 answer:\newline(A) A=14412A=\frac{144}{12}\newline(B) A=1224xA=12^{24 x}\newline(C) A=1.441.2A=1.44^{1.2}\newline(D) A=1.441.2A=1.44^{-1.2}

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Q. What is the value of AA when we rewrite 1.441.2x1.44^{-1.2 x} as AxA^{x} ?\newlineChoose 11 answer:\newline(A) A=14412A=\frac{144}{12}\newline(B) A=1224xA=12^{24 x}\newline(C) A=1.441.2A=1.44^{1.2}\newline(D) A=1.441.2A=1.44^{-1.2}
  1. Identify Base A: To rewrite 1.44(1.2x)1.44^{(-1.2 x)} in the form A(x)A^{(x)}, we need to find a base AA such that raising AA to the power of xx gives us the same expression as 1.441.44 raised to the power of 1.2-1.2 times xx. This means we need to find a value for AA that, when raised to the power of xx, is equivalent to 1.441.44 raised to the power of 1.2-1.2 times xx.
  2. Rewrite Expression: We can rewrite the expression 1.44(1.2x)1.44^{(-1.2 x)} as (1.44(1.2))x(1.44^{(-1.2)})^x. This is because when we raise a power to a power, we multiply the exponents. So, AA should be equal to 1.44(1.2)1.44^{(-1.2)}.
  3. Calculate A: Now we calculate A=1.441.2A = 1.44^{-1.2}. This is a straightforward calculation using the properties of exponents.
  4. Verify Answer: Looking at the answer choices, we see that option (D) A=1.441.2A=1.44^{-1.2} matches our calculation for AA. Therefore, the correct answer is (D) A=1.441.2A=1.44^{-1.2}.

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