Q. What is the total number of different 11-letter arrangements that can be formed using the letters in the word GALVANIZING?Answer:
Word Analysis: The word GALVANIZING has 11 letters with the following counts of identical letters: G−2, A−2, N−2, L−1, V−1, I−1, Z−1.
Permutations Formula: To find the total arrangements, we use the formula for permutations of a multiset: n1!×n2!×…×nk!n!, where n is the total number of items to arrange, and n1,n2,…,nk are the counts of identical items.
Calculate 11!: So, we calculate (2!⋅2!⋅2!)11! to account for the repeated G's, A's, and N's.
Calculate 2!: Calculating 11! gives us 39916800.
Calculate Total Sets: Calculating 2! for one set of identical letters gives us 2.
Divide to Get Total: Since we have three sets of identical letters, we calculate 2!×2!×2! which equals 8.
Divide to Get Total: Since we have three sets of identical letters, we calculate 2!×2!×2! which equals 8.Now, we divide 39916800 by 8 to get the total number of different arrangements.
Divide to Get Total: Since we have three sets of identical letters, we calculate 2!×2!×2! which equals 8.Now, we divide 39916800 by 8 to get the total number of different arrangements.39916800÷8 equals 4989600.
More problems from Convert between customary and metric systems