Q. What is the total number of different 10-letter arrangements that can be formed using the letters in the word SUFFRAGIST?Answer:
Count Unique Letters: First, count the number of each unique letter in SUFFRAGIST. S=2, U=1, F=2, R=1, A=1, G=1, I=1, T=1.
Calculate Total Arrangements: Since there are 10 letters in total, the number of different arrangements without considering repeating letters is 10! (10 factorial).Calculate 10!=10×9×8×7×6×5×4×3×2×1.
Account for Repeating Letters: Now, we need to account for the repeating letters. There are 2 S's and 2 F's.The number of arrangements for these repeating letters is 2! for each set of repeating letters.Calculate 2! for S's which is 2×1 and 2! for F's which is also 2×1.
Divide Total by Factorials: Divide the total number of arrangements by the product of the factorials of the counts of each repeating letter to correct for overcounting.So, divide 10! by (2!×2!).
Perform Division: Perform the division: (10!)/(2!×2!)=(10×9×8×7×6×5×4×3×2×1)/((2×1)×(2×1)).
Simplify Calculation: Simplify the calculation: (10×9×8×7×6×5×4×3)/(2×2)=(10×9×8×7×6×5×4×3)/4.
Finish Calculation: Finish the calculation: 410×9×8×7×6×5×4×3=10×9×8×7×6×5×2×3.
Final Answer: The final answer is the product of these numbers: 10×9×8×7×6×5×2×3=1814400.
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