What is the slope of the line through (-9,6) and (-6,-9) ? Choose 1 answer: (A) -(1)/(5) (B) -5 (c) (1)/(5) (D) 5

Identify slope formula: Identify the slope formula. The slope of a line through two points (x1, y1) and (x2, y2) is given by the formula: Slope = (y2 - y1) / (x2 - x1)Substitute given points: Substitute the given points into the slope formula. We have the points (-9, 6) and (-6, -9), so we assign x1 = -9, y1 = 6, x2 = -6, and y2 = -9. Slope = (-9 - 6) / (-6 - (-9))Calculate change in y: Calculate the change in y (y2 - y1). Change in y = -9 - 6 = -15Calculate change in x: Calculate the change in x (x2 - x1). Change in x = -6 - (-9) = -6 + 9 = 3Calculate slope: Calculate the slope using the changes in y and x. Slope = (-15) / (3) = -5

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What is the slope of the line through
(-9,6) and
(-6,-9) ?
Choose 1 answer:
(A)
-(1)/(5)
(B) -5
(c)
(1)/(5)
(D) 5

What is the slope of the line through $(-9,6)$ and $(-6,-9)$ ? $\newline$ Choose $1$ answer: $\newline$ (A) $-\frac{1}{5}$ $\newline$ (B) $-5$ $\newline$ (C) $\frac{1}{5}$ $\newline$ (D) $5$

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Math Problems

Algebra 1

Find the slope from two points

Full solution

Q. What is the slope of the line through

(-9,6)

and

(-6,-9)

\newline

Choose

1

answer:

\newline

(A)

-\frac{1}{5}

\newline

(B)

-5

\newline

(C)

\frac{1}{5}

\newline

(D)

5

Identify slope formula: Identify the slope formula. $\newline$ The slope of a line through two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the formula: $\newline$ Slope = $\frac{y_2 - y_1}{x_2 - x_1}$
Substitute given points: Substitute the given points into the slope formula. $\newline$ We have the points $(-9, 6)$ and $(-6, -9)$ , so we assign $x_1 = -9$ , $y_1 = 6$ , $x_2 = -6$ , and $y_2 = -9$ . $\newline$ Slope = $\frac{-9 - 6}{-6 - (-9)}$
Calculate change in y: Calculate the change in y $y_2 - y_1$ . $\newline$ Change in y = $-9 - 6 = -15$
Calculate change in x: Calculate the change in $x$ ( $x_2 - x_1$ ). $\newline$ Change in $x = -6 - (-9) = -6 + 9 = 3$
Calculate slope: Calculate the slope using the changes in $y$ and $x$ . $\text{Slope} = \frac{-15}{3} = -5$