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What is the modulus (absolute value) of 
6-8i ?
Don't round. If necessary, express your answer as a radical.

|6-8i|=

What is the modulus (absolute value) of 68i 6-8 i ?\newlineDon't round. If necessary, express your answer as a radical.\newline68i= |6-8 i|=

Full solution

Q. What is the modulus (absolute value) of 68i 6-8 i ?\newlineDon't round. If necessary, express your answer as a radical.\newline68i= |6-8 i|=
  1. Understanding the modulus: Understand the modulus of a complex number. The modulus of a complex number a+bia + bi is given by the square root of the sum of the squares of its real part (aa) and its imaginary part (bb). In mathematical terms, a+bi=a2+b2|a + bi| = \sqrt{a^2 + b^2}. For the complex number 68i6 - 8i, a=6a = 6 and b=8b = -8.
  2. Calculating squares: Calculate the squares of the real and imaginary parts.\newlineSquare the real part: 62=366^2 = 36.\newlineSquare the imaginary part: (8)2=64(-8)^2 = 64.
  3. Adding squares: Add the squares of the real and imaginary parts.\newlineSum of the squares: 36+64=10036 + 64 = 100.
  4. Finding the modulus: Take the square root of the sum to find the modulus. The square root of 100100 is 1010. Therefore, the modulus of 68i6 - 8i is 1010.

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