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What is the inverse of the function \newliney=log3xy=\log_{3}x?\newline(11) y=x3y=x^{3}\newline(33) y=3xy=3^{x}\newline(22) y=logx3y=\log_{x}3\newline(44) x=31yx=3^{1y}

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Q. What is the inverse of the function \newliney=log3xy=\log_{3}x?\newline(11) y=x3y=x^{3}\newline(33) y=3xy=3^{x}\newline(22) y=logx3y=\log_{x}3\newline(44) x=31yx=3^{1y}
  1. Definition of Inverse Function: Understand the definition of an inverse function.\newlineThe inverse function of y=log3(x)y = \log_{3}(x) is a function that will give back the original input xx when applied to the output yy. In other words, if we have y=log3(x)y = \log_{3}(x), then the inverse function applied to yy should give us xx.
  2. Express in Exponential Form: Express the original function in exponential form.\newlineTo find the inverse, we can rewrite the logarithmic equation y=log3(x)y = \log_{3}(x) in its equivalent exponential form. This is done by using the definition of a logarithm: if y=logb(x)y = \log_{b}(x), then by=xb^{y} = x. Applying this to our function, we get 3y=x3^{y} = x.
  3. Swap xx and yy: Swap xx and yy to find the inverse function.\newlineTo find the inverse function, we switch the roles of xx and yy. This means we will now have x=3yx = 3^y.
  4. Solve for yy: Solve for yy to express the inverse function.\newlineNow we need to express yy in terms of xx. Since x=3yx = 3^y, we can take the logarithm base 33 of both sides to isolate yy. This gives us y=log3(x)y = \log_{3}(x). Therefore, the inverse function is y=log3(x)y = \log_{3}(x).

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