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What is the inverse of the function

{:[f(x)=-(1)/(2)(x+3)?],[f^(-1)(x)=◻]:}

What is the inverse of the function\newlinef(x)=12(x+3)?f1(x)= \begin{array}{l} f(x)=-\frac{1}{2}(x+3) ? \\ f^{-1}(x)=\square \end{array}

Full solution

Q. What is the inverse of the function\newlinef(x)=12(x+3)?f1(x)= \begin{array}{l} f(x)=-\frac{1}{2}(x+3) ? \\ f^{-1}(x)=\square \end{array}
  1. Switch Roles and Solve: To find the inverse of the function f(x)=12(x+3)f(x) = -\frac{1}{2}(x + 3), we need to switch the roles of xx and f(x)f(x) and then solve for the new xx. Let y=f(x)y = f(x), so we have y=12(x+3)y = -\frac{1}{2}(x + 3). Now, replace yy with xx to get x=12(y+3)x = -\frac{1}{2}(y + 3).
  2. Replace yy with xx: Next, we need to solve for yy. Start by multiplying both sides of the equation by 2-2 to get rid of the fraction.\newline2x=y+3-2x = y + 3
  3. Multiply by 2-2: Now, subtract 33 from both sides to isolate yy.2x3=y-2x - 3 = y
  4. Isolate y: Finally, we write the inverse function by replacing yy with f1(x)f^{-1}(x).f1(x)=2x3f^{-1}(x) = -2x - 3

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