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(-13+16 i)-(3+4i)=
Express your answer in the form 
(a+bi).

(13+16i)(3+4i)= (-13+16 i)-(3+4 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .

Full solution

Q. (13+16i)(3+4i)= (-13+16 i)-(3+4 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .
  1. Identify complex numbers: Identify the real and imaginary parts of each complex number.\newlineThe first complex number is (13+16i)(-13+16i), where 13-13 is the real part and 16i16i is the imaginary part.\newlineThe second complex number is (3+4i)(3+4i), where 33 is the real part and 4i4i is the imaginary part.
  2. Subtract real parts: Subtract the real parts of the complex numbers.\newlineSubtract the real part of the second complex number from the real part of the first complex number.\newlineReal part calculation: (13)(3)=133=16(-13) - (3) = -13 - 3 = -16
  3. Subtract imaginary parts: Subtract the imaginary parts of the complex numbers.\newlineSubtract the imaginary part of the second complex number from the imaginary part of the first complex number.\newlineImaginary part calculation: (16i)(4i)=16i4i=12i(16i) - (4i) = 16i - 4i = 12i
  4. Combine real and imaginary parts: Combine the results of the real and imaginary parts.\newlineCombine the results from Step 22 and Step 33 to get the final answer in the form (a+bi)(a+bi).\newlineFinal answer: (16)+(12i)(-16) + (12i) = 16-16 + 1212i

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