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(7-10 i)-(3+30 i)=
Express your answer in the form 
(a+bi).

(710i)(3+30i)= (7-10 i)-(3+30 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .

Full solution

Q. (710i)(3+30i)= (7-10 i)-(3+30 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .
  1. Write down complex numbers: Write down the given complex numbers and the operation to be performed.\newlineWe are given two complex numbers, (710i)(7-10i) and (3+30i)(3+30i), and we need to subtract the second one from the first one.
  2. Perform subtraction of real and imaginary parts: Perform the subtraction by subtracting the real parts and the imaginary parts separately.\newlineSubtract the real part of the second complex number from the real part of the first complex number: 737 - 3.\newlineSubtract the imaginary part of the second complex number from the imaginary part of the first complex number: 10i30i-10i - 30i.
  3. Calculate subtraction of real parts: Calculate the subtraction of the real parts. 73=47 - 3 = 4
  4. Calculate subtraction of imaginary parts: Calculate the subtraction of the imaginary parts. 10i30i=40i-10i - 30i = -40i
  5. Combine results in (a+bi)(a+bi) form: Combine the results of the real part and the imaginary part to express the answer in the form (a+bi)(a+bi).\newlineThe result of the subtraction is 44 (from the real parts) and 40i-40i (from the imaginary parts), so the answer in the form (a+bi)(a+bi) is 440i4 - 40i.

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