Q. What is the focus of the parabola y=−8x2+1? Simplify any fractions.
Identify Parabola Form: Identify the form of the parabola and its orientation.Given equation: y=−8x2+1.This is a vertical parabola since it's in the form y=ax2+k.
Convert to Vertex Form: Convert the equation to vertex form and identify a, h, and k. The equation y=−8x2+1 is already in the form y=a(x−h)2+k where a=−8, h=0, and k=1.
Calculate Value of p: Calculate the value of p using the formula p=4a1.Substitute a=−8 into p=4a1.p=4(−8)1=−321=−321.
Determine Focus: Determine the focus of the parabola using the vertex (h,k) and the value of p. The vertex is (0,1). Since the parabola opens downwards (a < 0), the focus is at (0,k+p). Focus = (0,1−321)=(0,3231).
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