The equation of a circle is x^(2)+(y+4)^(2)=1. What are the center and radius of the circle? Choose 1 answer: (A) The center is (-4,0) and the radius is 1 . (B) The center is (4,0) and the radius is 1 . (C) The center is (0,4) and the radius is 1 . (D) The center is (0,-4) and the radius is 1 .

Identify standard form: Identify the standard form of a circle's equation. The standard form of a circle's equation is (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius.Compare to given equation: Compare the given equation to the standard form. The given equation is x² + (y + 4)² = 1. To match the standard form, we can see that h = 0 and k = -4, since there is no (x - h) term and the (y + 4) term corresponds to (y - (-4)).Determine the radius: Determine the radius of the circle. The right side of the equation is 1, which is the radius squared. Therefore, the radius r is the square root of 1, which is 1.Identify center and radius: Identify the center and radius from the comparison. The center of the circle is (h, k) = (0, -4), and the radius is 1.

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The equation of a circle is
x^(2)+(y+4)^(2)=1. What are the center and radius of the circle?
Choose 1 answer:
(A) The center is
(-4,0) and the radius is 1 .
(B) The center is
(4,0) and the radius is 1 .
(C) The center is
(0,4) and the radius is 1 .
(D) The center is
(0,-4) and the radius is 1 .

The equation of a circle is $x^{2}+(y+4)^{2}=1$ . What are the center and radius of the circle? $\newline$ Choose $1$ answer: $\newline$ (A) The center is $(-4,0)$ and the radius is $1$ . $\newline$ (B) The center is $(4,0)$ and the radius is $1$ . $\newline$ (C) The center is $(0,4)$ and the radius is $1$ . $\newline$ (D) The center is $(0,-4)$ and the radius is $1$ .

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Algebra 2

Convert equations of parabolas from general to vertex form

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Q. The equation of a circle is

x^{2}+(y+4)^{2}=1

. What are the center and radius of the circle?

\newline

Choose

1

answer:

\newline

(A) The center is

(-4,0)

and the radius is

1

\newline

(B) The center is

(4,0)

and the radius is

1

\newline

(0,4)

and the radius is

1

\newline

(D) The center is

(0,-4)

and the radius is

1

Identify standard form: Identify the standard form of a circle's equation. $\newline$ The standard form of a circle's equation is $(x - h)^2 + (y - k)^2 = r^2$ , where $(h, k)$ is the center of the circle and $r$ is the radius.
Compare to given equation: Compare the given equation to the standard form. $\newline$ The given equation is $x^2 + (y + 4)^2 = 1$ . To match the standard form, we can see that $h = 0$ and $k = -4$ , since there is no $(x - h)$ term and the $(y + 4)$ term corresponds to $(y - (-4))$ .
Determine the radius: Determine the radius of the circle. $\newline$ The right side of the equation is $1$ , which is the radius squared. Therefore, the radius $r$ is the square root of $1$ , which is $1$ .
Identify center and radius: Identify the center and radius from the comparison. $\newline$ The center of the circle is $(h, k) = (0, -4)$ , and the radius is $1$ .