The equation of a parabola is y=x2−10x+25. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Q. The equation of a parabola is y=x2−10x+25. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Identify vertex form: Identify the vertex form of a parabola.The vertex form of a parabola is given by the equation y=a(x−h)2+k, where (h,k) is the vertex of the parabola.
Complete square:Complete the square to rewrite the given equation in vertex form.The given equation is y=x2−10x+25. To complete the square, we need to express the quadratic term and the linear term as a perfect square trinomial.
Find square of half: Find the square of half the coefficient of x.The coefficient of x is −10. Half of this coefficient is −10/2, which is −5. Squaring −5 gives us 25.
Write as perfect square trinomial: Write the equation as a perfect square trinomial.Since the constant term 25 is already the square of −5, we can write the equation as y=(x−5)2. This is because x2−10x+25 is equivalent to (x−5)2.
Write final equation in vertex form: Write the final equation in vertex form.The equation y=(x−5)2 is already in vertex form, with the vertex being (5,0).
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