What is the focus of the parabola y = 7x^2? Simplify any fractions. (______,______)

Identify values: Identify the values of a, h, and k using the standard form y = ax^2 + bx + c, where the vertex form is y = a(x - h)^2 + k. For y = 7x^2, a = 7, h = 0, and k = 0.Calculate p: Calculate the value of p using the formula p = 1/(4a). p = 1/(4*7) p = 1/28Find focus: Find the focus of the parabola using the vertex (h, k) and the value of p. Since the parabola is vertical, the focus is (h, k + p). Focus = (0, 0 + 1/28) Focus = (0, 1/28)

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What is the focus of the parabola $y = 7x^2$ ? $\newline$ Simplify any fractions. $\newline$ (,)

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Algebra 2

Find the focus or directrix of a parabola

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Q. What is the focus of the parabola

y = 7x^2

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Simplify any fractions.

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(______,______)

Identify values: Identify the values of $a$ , $h$ , and $k$ using the standard form $y = ax^2 + bx + c$ , where the vertex form is $y = a(x - h)^2 + k$ . For $y = 7x^2$ , $a = 7$ , $h = 0$ , and $k = 0$ .
Calculate $p$ : Calculate the value of $p$ using the formula $p = \frac{1}{4a}$ . $p = \frac{1}{4\times7}$ $p = \frac{1}{28}$
Find focus: Find the focus of the parabola using the vertex $(h, k)$ and the value of $p$ . $\newline$ Since the parabola is vertical, the focus is $(h, k + p)$ . $\newline$ Focus = $(0, 0 + \frac{1}{28})$ $\newline$ Focus = $(0, \frac{1}{28})$