What is the focus of the parabola y = 5x^2 + 6? Simplify any fractions. (______,______)

Identify vertex form: Identify the vertex form of the parabola. y = 5x^2 + 6 can be written as y = 5(x - 0)^2 + 6, where a = 5, h = 0, and k = 6.Calculate p value: Calculate the value of p using the formula p = 1/(4a). p = 1/(4*5) p = 1/20Determine focus: Determine the focus of the parabola using the vertex (h, k) and the value of p. Since the parabola opens upwards, the focus is at (h, k + p). Focus = (0, 6 + 1/20) Focus = (0, 6.05)

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What is the focus of the parabola $y = 5x^2 + 6$ ? $\newline$ Simplify any fractions. $\newline$ (,)

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Algebra 2

Find the focus or directrix of a parabola

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Q. What is the focus of the parabola

y = 5x^2 + 6

\newline

Simplify any fractions.

\newline

(______,______)

Identify vertex form: Identify the vertex form of the parabola. $\newline$ $y = 5x^2 + 6$ can be written as $y = 5(x - 0)^2 + 6$ , where $a = 5$ , $h = 0$ , and $k = 6$ .
Calculate p value: Calculate the value of p using the formula $p = \frac{1}{4a}$ . $p = \frac{1}{4\times5}$ $p = \frac{1}{20}$
Determine focus: Determine the focus of the parabola using the vertex $(h, k)$ and the value of $p$ . $\newline$ Since the parabola opens upwards, the focus is at $(h, k + p)$ . $\newline$ Focus = $(0, 6 + \frac{1}{20})$ $\newline$ Focus = $(0, 6.05)$