Express as Sum/Difference: To find the exact value of tan(1219π), we can express 1219π as a sum or difference of angles for which we know the exact values of the trigonometric functions. The angles we commonly use are multiples of 6π, 4π, and 3π because their trigonometric values are well known and can be easily calculated.
Apply Angle Sum Identity: We can express (19π)/12 as the sum of (16π)/12 and (3π)/12, which simplifies to (4π)/3+π/4. These two angles are more familiar, and we can use the angle sum identity for tangent to find the exact value of tan((19π)/12).
Calculate Exact Values: The angle sum identity for tangent is tan(A+B)=1−tan(A)tan(B)tan(A)+tan(B). We will use A=34π and B=4π for our calculation.
Plug into Identity: First, we find the exact values of tan(34π) and tan(4π). tan(34π) is equivalent to tan(π−3π), which is the same as −tan(3π) because tangent is negative in the third quadrant. The exact value of tan(3π) is 3, so tan(34π)=−3. tan(4π) is 1 because it's the tangent of a tan(4π)0-degree angle.
Simplify Expression: Now we can plug these values into the angle sum identity: tan(1219π)=tan(34π+4π)=1−(−3⋅1)−3+1.
Rationalize Denominator: Simplifying the expression, we get tan(1219π)=1+3−3+1. To rationalize the denominator, we multiply the numerator and the denominator by the conjugate of the denominator, which is (1−3).
Expand Numerator: Multiplying the numerator and denominator by the conjugate, we get: tan(1219π)=[1+3][1−3][−3+1][1−3].
Expand Denominator: Expanding the numerator, we get: (−3+1)(1−3)=−3−3+3−1. The 3 terms cancel out, leaving us with −3−1.
Final Simplification: Expanding the denominator, we get: (1+3)(1−3)=1−3, which simplifies to −2.
Final Simplification: Expanding the denominator, we get: (1+3)(1−3)=1−3, which simplifies to −2.Now we have tan(1219π)=−2−4, which simplifies to 2.
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