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What is the diameter of a sphere with a volume of 
1352cm^(3), to the nearest tenth of a centimeter?
Answer: 
cm

What is the diameter of a sphere with a volume of 1352 cm3 1352 \mathrm{~cm}^{3} , to the nearest tenth of a centimeter?\newlineAnswer: cm \mathrm{cm}

Full solution

Q. What is the diameter of a sphere with a volume of 1352 cm3 1352 \mathrm{~cm}^{3} , to the nearest tenth of a centimeter?\newlineAnswer: cm \mathrm{cm}
  1. Identify formula for volume: Identify the formula to calculate the volume of a sphere.\newlineThe formula for the volume VV of a sphere in terms of its radius rr is V=43πr3V = \frac{4}{3}\pi r^3.
  2. Rearrange formula for radius: Rearrange the formula to solve for the radius.\newlineTo find the radius, we need to rearrange the formula to solve for rr. This gives us r=(3V4π)13r = \left(\frac{3V}{4\pi}\right)^{\frac{1}{3}}.
  3. Substitute given volume: Substitute the given volume into the rearranged formula.\newlineWe know the volume V=1352 cm3V = 1352 \text{ cm}^3, so we substitute this value into the formula to find the radius: r=(3×1352 cm34π)13r = \left(\frac{3 \times 1352 \text{ cm}^3}{4\pi}\right)^{\frac{1}{3}}.
  4. Calculate radius: Calculate the radius using the substituted values.\newliner=(3×1352 cm34π)13=(4056 cm34π)13r = \left(\frac{3\times 1352 \text{ cm}^3}{4\pi}\right)^{\frac{1}{3}} = \left(\frac{4056 \text{ cm}^3}{4\pi}\right)^{\frac{1}{3}}.
  5. Evaluate expression for radius: Evaluate the expression to find the radius.\newliner(4056 cm312.5664)13(322.637 cm3)136.879 cmr \approx (\frac{4056 \text{ cm}^3}{12.5664})^{\frac{1}{3}} \approx (322.637 \text{ cm}^3)^{\frac{1}{3}} \approx 6.879 \text{ cm} (rounded to three decimal places for intermediate calculation).
  6. Calculate sphere diameter: Calculate the diameter of the sphere.\newlineThe diameter dd is twice the radius, so d=2rd = 2r. Therefore, d=2×6.879cm13.758cmd = 2 \times 6.879 \, \text{cm} \approx 13.758 \, \text{cm}.
  7. Round diameter to nearest tenth: Round the diameter to the nearest tenth of a centimeter.\newlineThe diameter rounded to the nearest tenth is approximately 13.8cm.13.8\,\text{cm}.

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