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What is the conjugate of 
-(7)/(3)+(4)/(3)i ?

(4)/(3)-(7)/(3)i

-(7)/(3)-(4)/(3)i

(7)/(3)-(4)/(3)i

(7)/(3)+(4)/(3)i

What is the conjugate of 73+43i -\frac{7}{3}+\frac{4}{3} i ?\newline4373i \frac{4}{3}-\frac{7}{3} i \newline7343i -\frac{7}{3}-\frac{4}{3} i \newline7343i \frac{7}{3}-\frac{4}{3} i \newline73+43i \frac{7}{3}+\frac{4}{3} i

Full solution

Q. What is the conjugate of 73+43i -\frac{7}{3}+\frac{4}{3} i ?\newline4373i \frac{4}{3}-\frac{7}{3} i \newline7343i -\frac{7}{3}-\frac{4}{3} i \newline7343i \frac{7}{3}-\frac{4}{3} i \newline73+43i \frac{7}{3}+\frac{4}{3} i
  1. Understand Complex Conjugate: Understand the concept of a complex conjugate. The conjugate of a complex number a+bia + bi is abia - bi, where aa and bb are real numbers and ii is the imaginary unit.
  2. Identify Real and Imaginary Parts: Identify the real and imaginary parts of the given complex number.\newlineThe given complex number is 73+43i-\frac{7}{3} + \frac{4}{3}i. Here, the real part is 73-\frac{7}{3} and the imaginary part is 43\frac{4}{3}.
  3. Apply Conjugate Rule: Apply the conjugate rule to the given complex number.\newlineTo find the conjugate, we change the sign of the imaginary part. Therefore, the conjugate of 73+43i-\frac{7}{3} + \frac{4}{3}i is 7343i-\frac{7}{3} - \frac{4}{3}i.

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