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What is (f−g)(x)(f - g)(x)?\newlinef(x)=−2x+1f(x) = -2x + 1\newlineg(x)=−4xg(x) = -4x\newlineWrite your answer as a polynomial or a rational function in simplest form.\newline______

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Add and subtract functionsright chevron icon

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Q. What is (f−g)(x)(f - g)(x)?\newlinef(x)=−2x+1f(x) = -2x + 1\newlineg(x)=−4xg(x) = -4x\newlineWrite your answer as a polynomial or a rational function in simplest form.\newline______
  1. Identify Formula: Identify the formula for (f−g)(x)(f - g)(x).(f−g)(x)(f - g)(x) is the difference of f(x)f(x) and g(x)g(x).(f−g)(x)=f(x)−g(x)(f - g)(x) = f(x) - g(x)
  2. Substitute Functions: We have: \newlinef(x)=−2x+1f(x) = -2x + 1 \newlineg(x)=−4xg(x) = -4x \newlineNow, substitute these functions into the formula for (f−g)(x)(f - g)(x).\newline(f−g)(x)=(−2x+1)−(−4x)(f - g)(x) = (-2x + 1) - (-4x)
  3. Simplify Expression: Simplify the expression by distributing the negative sign and combining like terms.\newline(f−g)(x)=−2x+1+4x(f - g)(x) = -2x + 1 + 4x\newline(f−g)(x)=2x+1(f - g)(x) = 2x + 1

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