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Wei is standing in wavy water and notices the depth of the waves varies in a periodic way that can be modeled by a trigonometric function. He starts a stopwatch to time the waves. After 1.11.1 seconds, and then again every 33 seconds, the water just touches his knees. Between peaks, the water recedes to his ankles. Wei's ankles are 12cm12\,\text{cm} off the ocean floor, and his knees are 55cm55\,\text{cm} off the ocean floor. Find the formula of the trigonometric function that models the depth DD of the water tt seconds after Wei starts the stopwatch. Define the function using radians.\newlineD(t)=D(t)=\square

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Q. Wei is standing in wavy water and notices the depth of the waves varies in a periodic way that can be modeled by a trigonometric function. He starts a stopwatch to time the waves. After 1.11.1 seconds, and then again every 33 seconds, the water just touches his knees. Between peaks, the water recedes to his ankles. Wei's ankles are 12cm12\,\text{cm} off the ocean floor, and his knees are 55cm55\,\text{cm} off the ocean floor. Find the formula of the trigonometric function that models the depth DD of the water tt seconds after Wei starts the stopwatch. Define the function using radians.\newlineD(t)=D(t)=\square
  1. Determine Amplitude: Determine the amplitude of the wave.\newlineThe amplitude is half the distance between the maximum and minimum values of the wave's depth. The maximum depth is at Wei's knees (55cm55\,\text{cm}) and the minimum depth is at his ankles (12cm12\,\text{cm}).\newlineAmplitude (AA) = (Maximum depth - Minimum depth) / 22\newlineA=(55cm12cm)/2A = (55\,\text{cm} - 12\,\text{cm}) / 2\newlineA=43cm/2A = 43\,\text{cm} / 2\newlineA=21.5cmA = 21.5\,\text{cm}
  2. Determine Vertical Shift: Determine the vertical shift.\newlineThe vertical shift is the average of the maximum and minimum values of the wave's depth.\newlineVertical shift D0D_0 = Maximum depth+Minimum depth2\frac{\text{Maximum depth} + \text{Minimum depth}}{2}\newlineD0=55cm+12cm2D_0 = \frac{55 \, \text{cm} + 12 \, \text{cm}}{2}\newlineD0=67cm2D_0 = \frac{67 \, \text{cm}}{2}\newlineD0=33.5cmD_0 = 33.5 \, \text{cm}
  3. Determine Period: Determine the period of the wave.\newlineThe period TT is the time it takes for the wave to complete one full cycle. Wei notices that the water touches his knees every 33 seconds, which means the period is 33 seconds.
  4. Convert to Radians: Convert the period from seconds to radians.\newlineSince the trigonometric function will be defined using radians, we need to find the angular frequency (ω\omega), which is 2π2\pi divided by the period (TT).\newlineω=2πT\omega = \frac{2\pi}{T}\newlineω=2π3\omega = \frac{2\pi}{3}
  5. Determine Phase Shift: Determine the phase shift.\newlineThe phase shift is the horizontal shift of the function. Since the water touches Wei's knees at t=1.1t = 1.1 seconds, and this is the first time it happens after he starts the stopwatch, the phase shift will be to the right by 1.11.1 seconds.\newlinePhase shift (φ\varphi) = ω×time shift-\omega \times \text{time shift}\newlineφ=2π3×1.1\varphi = -\frac{2\pi}{3} \times 1.1\newlineφ=2π×1.13\varphi = -\frac{2\pi \times 1.1}{3}\newlineφ=2.2π3\varphi = -\frac{2.2\pi}{3}
  6. Write Trig Function: Write the trigonometric function.\newlineThe general form of a sinusoidal function is D(t)=Asin(ωt+φ)+D0D(t) = A \cdot \sin(\omega t + \varphi) + D_0.\newlineSubstitute the values of AA, ω\omega, φ\varphi, and D0D_0 into the equation.\newlineD(t)=21.5sin(2π3t2.2π3)+33.5D(t) = 21.5 \cdot \sin\left(\frac{2\pi}{3}t - \frac{2.2\pi}{3}\right) + 33.5

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