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Calvin and Melvin are two of Santa's elves. The number of toys they build is given by
11 c+8m, where
c is the number of candy canes Calvin eats for breakfast and
m is the number of candy canes Melvin eats for breakfast. How many toys do they build when Calvin eats 5 candy canes and Melvin eats 3 candy canes for breakfast?

Calvin and Melvin are two of Santa's elves. The number of toys they build is given by $11 c+8 m$ , where $c$ is the number of candy canes Calvin eats for breakfast and $m$ is the number of candy canes Melvin eats for breakfast. How many toys do they build when Calvin eats $5$ candy canes and Melvin eats $3$ candy canes for breakfast?

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Find a value using two-variable equations: word problems

Full solution

Q. Calvin and Melvin are two of Santa's elves. The number of toys they build is given by

11 c+8 m

, where

c

is the number of candy canes Calvin eats for breakfast and

m

is the number of candy canes Melvin eats for breakfast. How many toys do they build when Calvin eats

5

candy canes and Melvin eats

3

candy canes for breakfast?

Identify Values: Identify the given values for $c$ and $m$ . $\newline$ Calvin eats $5$ candy canes for breakfast, so $c = 5$ . $\newline$ Melvin eats $3$ candy canes for breakfast, so $m = 3$ .
Plug in Expression: Plug in the values of $c$ and $m$ into the expression $11c + 8m$ . $11c + 8m$ becomes $11(5) + 8(3)$ .
Perform Multiplication: Perform the multiplication. $\newline$ $11(5) = 55$ and $8(3) = 24$ .
Add Results: Add the results of the multiplication to find the total number of toys built. $55 + 24 = 79$ .

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