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\newlinev \cdot (j + y) = 6161y + 8282 value of y\newline

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Find derivatives using the quotient rule IIright chevron icon

Full solution

Q. \newlinev \cdot (j + y) = 6161y + 8282 value of y\newline
  1. Distribute and rearrange: First, distribute vv on the left side: v⋅j+v⋅y=61y+82v \cdot j + v \cdot y = 61y + 82.
  2. Isolate y terms: Next, isolate the yy terms on one side: v⋅y−61y=82−v⋅jv \cdot y - 61y = 82 - v \cdot j.
  3. Factor out y: Factor out yy on the left side: y(v−61)=82−v⋅jy(v - 61) = 82 - v \cdot j.
  4. Solve for y: Solve for yy: y=82−v⋅jv−61y = \frac{82 - v \cdot j}{v - 61}.

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