Q. Using implicit differentiation, find dxdy.xy=−2+yx3
Identify Equation: Identify the equation that needs to be differentiated implicitly.Equation: xy=−2+yx3
Differentiate Both Sides: Differentiate both sides of the equation with respect to x, remembering to apply the product rule to xy and yx3, and the chain rule to xy.dxd(xy)=dxd(−2+yx3)
Apply Chain Rule: Apply the chain rule to the left side: dxd(u)=21u−21⋅dxdu, where u=xy. dxd(xy)=21(xy)−21⋅dxd(xy)
Apply Product Rule: Apply the product rule to dxd(xy): dxd(uv)=u′v+uv′, where u=x and v=y. dxd(xy)=dxd(x)y+x∗dxd(y) dxd(xy)=y+x(dxdy)
Substitute Result: Substitute the result from the product rule into the chain rule result.(21)(xy)−21⋅(y+xdxdy)
Differentiate Right Side: Differentiate the right side of the equation with respect to x, applying the product rule to yx3. dxd(−2+yx3)=dxd(−2)+dxd(yx3) dxd(−2+yx3)=0+dxd(yx3)
Apply Product Rule: Apply the product rule to dxd(yx3): dxd(uv)=u′v+uv′, where u=y and v=x3. dxd(yx3)=dxd(y)x3+y∗dxd(x3) dxd(yx3)=(dxdy)x3+y∗3x2
Combine Differentiated Results: Combine the differentiated results and set them equal to each other. (21)(xy)−21∗(y+xdxdy)=0+dxdyx3+y⋅3x2
Solve for dxdy: Solve for dxdy by isolating terms involving dxdy on one side of the equation.(21)(xy)−21⋅y+(21)(xy)−21⋅x(dxdy)=(dxdy)x3+y⋅3x2
Subtract Terms: Subtract dxdyx3 from both sides to get all dxdy terms on one side.(21)(xy)−21⋅xdxdy−dxdyx3=y⋅3x2−(21)(xy)−21⋅y
Factor out dxdy: Factor out dxdy on the left side of the equation.dxdy×(21(xy)−21×x−x3)=y×3x2−21(xy)−21×y
Divide Both Sides: Divide both sides by [(1/2)(xy)−1/2⋅x−x3] to solve for dxdy.dxdy=(1/2)(xy)−1/2⋅x−x3y⋅3x2−(1/2)(xy)−1/2⋅y
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