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Use the quadratic formula to solve. Express your answer in simplest form.

12v^(2)+13 v+1=6v
Answer: 
v=

Use the quadratic formula to solve. Express your answer in simplest form.\newline12v2+13v+1=6v 12 v^{2}+13 v+1=6 v \newlineAnswer: v= v=

Full solution

Q. Use the quadratic formula to solve. Express your answer in simplest form.\newline12v2+13v+1=6v 12 v^{2}+13 v+1=6 v \newlineAnswer: v= v=
  1. Set Equation Equal: First, we need to bring all terms to one side of the equation to set it equal to zero.\newline12v2+13v+16v=012v^2 + 13v + 1 - 6v = 0\newlineThis simplifies to:\newline12v2+7v+1=012v^2 + 7v + 1 = 0
  2. Use Quadratic Formula: Now we will use the quadratic formula to solve for vv, which is given by:\newlinev=b±b24ac2av = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\newlineFor our equation, a=12a = 12, b=7b = 7, and c=1c = 1.
  3. Calculate Discriminant: Next, we calculate the discriminant, which is the part under the square root in the quadratic formula:\newlineDiscriminant = b24acb^2 - 4ac\newlineDiscriminant = (7)24(12)(1)(7)^2 - 4(12)(1)\newlineDiscriminant = 494849 - 48\newlineDiscriminant = 11
  4. Apply Quadratic Formula: Since the discriminant is positive, we will have two real and distinct solutions. We can now plug the values of aa, bb, and cc into the quadratic formula:\newlinev=7±12×12v = \frac{-7 \pm \sqrt{1}}{2 \times 12}\newlinev=7±124v = \frac{-7 \pm 1}{24}
  5. Solve for Solutions: We will now solve for the two possible values of vv:
    First solution:
    v=(7+1)/24v = (-7 + 1) / 24
    v=6/24v = -6 / 24
    v=1/4v = -1/4

    Second solution:
    v=(71)/24v = (-7 - 1) / 24
    v=8/24v = -8 / 24
    v=1/3v = -1/3

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