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Tickets for a concert were 
$5 for each child and 
$8 for each adult. At one of the concerts, each adult brought 4 children with them, and 10 children attended without an adult. The total ticket sales were 
$1,730. Which of the following systems of equations can be solved to determine the number of children, 
c, and adults, 
a, who attended the concert?
Choose 1 answer:
(A) 
5c+8a=1,730

4a+10=c
(B) 
5c+8a=1,730

4a-10=c
(C) 
8c+5a=1,730

4a+10=c
(D) 
8c+5a=1,730

4a-10=c

Tickets for a concert were $5 \$ 5 for each child and $8 \$ 8 for each adult. At one of the concerts, each adult brought 44 children with them, and 1010 children attended without an adult. The total ticket sales were $1,730 \$ 1,730 . Which of the following systems of equations can be solved to determine the number of children, c c , and adults, a a , who attended the concert?\newlineChoose 11 answer:\newline(A) 5c+8a=1,730 5 c+8 a=1,730 \newline4a+10=c 4 a+10=c \newline(B) 5c+8a=1,730 5 c+8 a=1,730 \newline4a10=c 4 a-10=c \newline(C) 8c+5a=1,730 8 c+5 a=1,730 \newline4a+10=c 4 a+10=c \newline(D) 8c+5a=1,730 8 c+5 a=1,730 \newline4a10=c 4 a-10=c

Full solution

Q. Tickets for a concert were $5 \$ 5 for each child and $8 \$ 8 for each adult. At one of the concerts, each adult brought 44 children with them, and 1010 children attended without an adult. The total ticket sales were $1,730 \$ 1,730 . Which of the following systems of equations can be solved to determine the number of children, c c , and adults, a a , who attended the concert?\newlineChoose 11 answer:\newline(A) 5c+8a=1,730 5 c+8 a=1,730 \newline4a+10=c 4 a+10=c \newline(B) 5c+8a=1,730 5 c+8 a=1,730 \newline4a10=c 4 a-10=c \newline(C) 8c+5a=1,730 8 c+5 a=1,730 \newline4a+10=c 4 a+10=c \newline(D) 8c+5a=1,730 8 c+5 a=1,730 \newline4a10=c 4 a-10=c
  1. Translate into mathematical expressions: Translate the given information into mathematical expressions.\newlineWe know that each child's ticket costs $5\$5 and each adult's ticket costs $8\$8. The total sales from tickets are $1,730\$1,730. We also know that for each adult, there are 44 children, and there are 1010 additional children who attended without an adult. We can represent the number of children as cc and the number of adults as aa.
  2. Set up first equation: Set up the first equation based on the total ticket sales.\newlineThe total amount from children's tickets is 5c5c (since each child's ticket is $5\$5) and from adults' tickets is 8a8a (since each adult's ticket is $8\$8). The total sales are $1,730\$1,730, so the first equation is:\newline5c+8a=1,7305c + 8a = 1,730
  3. Set up second equation: Set up the second equation based on the relationship between the number of children and adults.\newlineEach adult brings 44 children, so the number of children brought by adults is 4a4a. There are also 1010 additional children who came without an adult. Therefore, the total number of children is the sum of children brought by adults and the children who came alone:\newlinec=4a+10c = 4a + 10
  4. Identify correct system: Identify the correct system of equations from the given options.\newlineWe have two equations from the previous steps:\newline11. 5c+8a=1,7305c + 8a = 1,730 (Total ticket sales)\newline22. c=4a+10c = 4a + 10 (Relationship between children and adults)\newlineNow we need to match these equations with the given options. The correct system of equations that matches our derived equations is:\newline(A) 5c+8a=1,7305c + 8a = 1,730\newline 4a+10=c4a + 10 = c

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