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Three points on the graph of the function 
f(x) are 
{(0,1),(1,2),(2,5)}. Which equation represents 
f(x) ?

f(x)=2^(x)

f(x)=3x-1

f(x)=x^(2)+1

f(x)=x+1

Three points on the graph of the function f(x) f(x) are {(0,1),(1,2),(2,5)} \{(0,1),(1,2),(2,5)\} . Which equation represents f(x) f(x) ?\newlinef(x)=2x f(x)=2^{x} \newlinef(x)=3x1 f(x)=3 x-1 \newlinef(x)=x2+1 f(x)=x^{2}+1 \newlinef(x)=x+1 f(x)=x+1

Full solution

Q. Three points on the graph of the function f(x) f(x) are {(0,1),(1,2),(2,5)} \{(0,1),(1,2),(2,5)\} . Which equation represents f(x) f(x) ?\newlinef(x)=2x f(x)=2^{x} \newlinef(x)=3x1 f(x)=3 x-1 \newlinef(x)=x2+1 f(x)=x^{2}+1 \newlinef(x)=x+1 f(x)=x+1
  1. Test f(x)=2xf(x)=2^{x}: Let's test each given function with the points provided to see which one fits all three points.\newlineFirst, we will test the point (0,1)(0,1) with each function.
  2. Test f(x)=3x1f(x)=3x-1: Testing f(x)=2xf(x)=2^{x} with the point (0,1)(0,1):f(0)=20=1f(0) = 2^{0} = 1. This matches the y-value of the point (0,1)(0,1).
  3. Test f(x)=x2+1f(x)=x^{2}+1: Testing f(x)=3x1f(x)=3x-1 with the point (0,1)(0,1):f(0)=3(0)1=1f(0) = 3(0) - 1 = -1. This does not match the y-value of the point (0,1)(0,1), so this function is not a match.
  4. Test f(x)=x+1f(x)=x+1: Testing f(x)=x2+1f(x)=x^{2}+1 with the point (0,1)(0,1):f(0)=(0)2+1=1f(0) = (0)^{2} + 1 = 1. This matches the y-value of the point (0,1)(0,1).
  5. Test f(x)=2xf(x)=2^{x}: Testing f(x)=x+1f(x)=x+1 with the point (0,1)(0,1):f(0)=0+1=1f(0) = 0 + 1 = 1. This matches the y-value of the point (0,1)(0,1).
  6. Test f(x)=x2+1f(x)=x^{2}+1: Now, let's test the point (1,2)(1,2) with the remaining functions that matched the first point.
  7. Test f(x)=x+1f(x)=x+1: Testing f(x)=2xf(x)=2^{x} with the point (1,2)(1,2):f(1)=21=2f(1) = 2^{1} = 2. This matches the y-value of the point (1,2)(1,2).
  8. Test f(x)=2xf(x)=2^{x}: Testing f(x)=x2+1f(x)=x^{2}+1 with the point (1,2)(1,2):f(1)=(1)2+1=2f(1) = (1)^{2} + 1 = 2. This matches the y-value of the point (1,2)(1,2).
  9. Test f(x)=x2+1f(x)=x^{2}+1: Testing f(x)=x+1f(x)=x+1 with the point (1,2)(1,2):f(1)=1+1=2f(1) = 1 + 1 = 2. This matches the y-value of the point (1,2)(1,2).
  10. Test f(x)=x2+1f(x)=x^{2}+1: Testing f(x)=x+1f(x)=x+1 with the point (1,2)(1,2):f(1)=1+1=2f(1) = 1 + 1 = 2. This matches the y-value of the point (1,2)(1,2).Finally, let's test the point (2,5)(2,5) with the remaining functions that matched the first two points.
  11. Test f(x)=x2+1f(x)=x^{2}+1: Testing f(x)=x+1f(x)=x+1 with the point (1,2)(1,2):f(1)=1+1=2f(1) = 1 + 1 = 2. This matches the y-value of the point (1,2)(1,2).Finally, let's test the point (2,5)(2,5) with the remaining functions that matched the first two points.Testing f(x)=2xf(x)=2^{x} with the point (2,5)(2,5):f(2)=22=4f(2) = 2^{2} = 4. This does not match the y-value of the point (2,5)(2,5), so this function is not a match.
  12. Test f(x)=x2+1f(x)=x^{2}+1: Testing f(x)=x+1f(x)=x+1 with the point (1,2)(1,2):f(1)=1+1=2f(1) = 1 + 1 = 2. This matches the y-value of the point (1,2)(1,2).Finally, let's test the point (2,5)(2,5) with the remaining functions that matched the first two points.Testing f(x)=2xf(x)=2^{x} with the point (2,5)(2,5):f(2)=22=4f(2) = 2^{2} = 4. This does not match the y-value of the point (2,5)(2,5), so this function is not a match.Testing f(x)=x2+1f(x)=x^{2}+1 with the point (2,5)(2,5):f(x)=x+1f(x)=x+122. This matches the y-value of the point (2,5)(2,5).
  13. Test f(x)=x2+1f(x)=x^{2}+1: Testing f(x)=x+1f(x)=x+1 with the point (1,2)(1,2):f(1)=1+1=2f(1) = 1 + 1 = 2. This matches the y-value of the point (1,2)(1,2).Finally, let's test the point (2,5)(2,5) with the remaining functions that matched the first two points.Testing f(x)=2xf(x)=2^{x} with the point (2,5)(2,5):f(2)=22=4f(2) = 2^{2} = 4. This does not match the y-value of the point (2,5)(2,5), so this function is not a match.Testing f(x)=x2+1f(x)=x^{2}+1 with the point (2,5)(2,5):f(x)=x+1f(x)=x+122. This matches the y-value of the point (2,5)(2,5).Testing f(x)=x+1f(x)=x+1 with the point (2,5)(2,5):f(x)=x+1f(x)=x+166. This does not match the y-value of the point (2,5)(2,5), so this function is not a match.

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