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Let’s check out your problem:
The sum of three consecutive
integers
is
−
39
-39
−
39
. Find the value of the least of the three.
\newline
Answer:
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Math Problems
Algebra 1
Consecutive integer problems
Full solution
Q.
The sum of three consecutive integers is
−
39
-39
−
39
. Find the value of the least of the three.
\newline
Answer:
Initialize First Integer:
Let
x
x
x
be the first (least) integer.
\newline
Consecutive integers increase by
1
1
1
each time.
\newline
Consecutive integers:
x
x
x
,
x
+
1
x+1
x
+
1
,
x
+
2
x+2
x
+
2
Set Up Equation:
Set up the equation that represents the sum of the three consecutive integers equal to
−
39
-39
−
39
.
\newline
Equation:
x
+
(
x
+
1
)
+
(
x
+
2
)
=
−
39
x + (x+1) + (x+2) = -39
x
+
(
x
+
1
)
+
(
x
+
2
)
=
−
39
Simplify Equation:
Simplify the left side of the equation
x
+
(
x
+
1
)
+
(
x
+
2
)
=
−
39
x + (x+1) + (x+2) = -39
x
+
(
x
+
1
)
+
(
x
+
2
)
=
−
39
.
x
+
(
x
+
1
)
+
(
x
+
2
)
=
−
39
x + (x+1) + (x+2) = -39
x
+
(
x
+
1
)
+
(
x
+
2
)
=
−
39
(
x
+
x
+
x
)
+
(
1
+
2
)
=
−
39
(x + x + x) + (1+2) = -39
(
x
+
x
+
x
)
+
(
1
+
2
)
=
−
39
3
x
+
3
=
−
39
3x + 3 = -39
3
x
+
3
=
−
39
Isolate Variable Term:
Isolate the variable term in
3
x
+
3
=
−
39
3x + 3 = -39
3
x
+
3
=
−
39
.
\newline
3
x
+
3
=
−
39
3x + 3 = -39
3
x
+
3
=
−
39
\newline
3
x
+
3
−
3
=
−
39
−
3
3x + 3 - 3 = -39 - 3
3
x
+
3
−
3
=
−
39
−
3
\newline
3
x
=
−
42
3x = -42
3
x
=
−
42
Solve for x:
Solve for x.
\newline
3
x
=
−
42
3x = -42
3
x
=
−
42
\newline
3
x
3
=
−
42
3
\frac{3x}{3} = \frac{-42}{3}
3
3
x
=
3
−
42
\newline
x
=
−
14
x = -14
x
=
−
14
Final Result:
We have found the value of
x
x
x
, which is the least of the three consecutive integers.
\newline
The least integer:
x
=
−
14
x = -14
x
=
−
14
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