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The sum of three consecutive integers is -39 . Find the value of the least of the three. Answer:

The sum of three consecutive integers is −39-39 . Find the value of the least of the three.\newlineAnswer:

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Full solution

Q. The sum of three consecutive integers is −39-39 . Find the value of the least of the three.\newlineAnswer:
  1. Initialize First Integer: Let xx be the first (least) integer.\newlineConsecutive integers increase by 11 each time.\newlineConsecutive integers: xx, x+1x+1, x+2x+2
  2. Set Up Equation: Set up the equation that represents the sum of the three consecutive integers equal to −39-39.\newlineEquation: x+(x+1)+(x+2)=−39x + (x+1) + (x+2) = -39
  3. Simplify Equation: Simplify the left side of the equation x+(x+1)+(x+2)=−39x + (x+1) + (x+2) = -39.
    x+(x+1)+(x+2)=−39x + (x+1) + (x+2) = -39
    (x+x+x)+(1+2)=−39(x + x + x) + (1+2) = -39
    3x+3=−393x + 3 = -39
  4. Isolate Variable Term: Isolate the variable term in 3x+3=−393x + 3 = -39.\newline3x+3=−393x + 3 = -39\newline3x+3−3=−39−33x + 3 - 3 = -39 - 3\newline3x=−423x = -42
  5. Solve for x: Solve for x.\newline3x=−423x = -42\newline3x3=−423\frac{3x}{3} = \frac{-42}{3}\newlinex=−14x = -14
  6. Final Result: We have found the value of xx, which is the least of the three consecutive integers.\newlineThe least integer: x=−14x = -14

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