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The River Rock Horse Rescue has a fenced-off pasture in the shape of a trapezoid. They need to calculate the area of the trapezoid to see how many horses it will safely hold. The bases of the trapezoid are 30meters30\,\text{meters} long and 20meters20\,\text{meters} long. The height of the trapezoid is 10meters10\,\text{meters}. Which equation can you use to find the area of the pasture, AA?\newlineChoices:\newline(A)A=12(10)(30+20)A = \frac{1}{2}(10)(30 + 20)\newline(B)A=12(20)(10+30)A = \frac{1}{2}(20)(10 + 30)\newlineWhat is the area of the pasture?\newlineWrite your answer as a whole number or decimal. Do not round.\newline____ square meters\newline

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Q. The River Rock Horse Rescue has a fenced-off pasture in the shape of a trapezoid. They need to calculate the area of the trapezoid to see how many horses it will safely hold. The bases of the trapezoid are 30meters30\,\text{meters} long and 20meters20\,\text{meters} long. The height of the trapezoid is 10meters10\,\text{meters}. Which equation can you use to find the area of the pasture, AA?\newlineChoices:\newline(A)A=12(10)(30+20)A = \frac{1}{2}(10)(30 + 20)\newline(B)A=12(20)(10+30)A = \frac{1}{2}(20)(10 + 30)\newlineWhat is the area of the pasture?\newlineWrite your answer as a whole number or decimal. Do not round.\newline____ square meters\newline
  1. Identify Formula: Step 11: Identify the formula to calculate the area of a trapezoid.\newlineThe formula for the area of a trapezoid is A=12×(base1+base2)×heightA = \frac{1}{2} \times (\text{base1} + \text{base2}) \times \text{height}. Here, base1=30\text{base1} = 30 meters, base2=20\text{base2} = 20 meters, and height=10\text{height} = 10 meters.
  2. Substitute Values: Step 22: Substitute the values into the formula.\newlineUsing the formula A=12×(base1+base2)×heightA = \frac{1}{2} \times (\text{base1} + \text{base2}) \times \text{height}, substitute the given values:\newlineA=12×(30+20)×10A = \frac{1}{2} \times (30 + 20) \times 10
  3. Perform Calculations: Step 33: Perform the calculations.\newlineCalculate the sum of the bases: 30+20=5030 + 20 = 50 meters.\newlineThen, calculate the area: A=12×50×10=250A = \frac{1}{2} \times 50 \times 10 = 250 square meters.

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