One of the legs of a right triangle measures 15cm and its hypotenuse measures 17cm. Find the measure of the other leg. If necessary, round to the nearest tenth. Answer: cm

Apply Pythagorean Theorem: To find the length of the other leg of the right triangle, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the other two sides (a and b). The formula is a^2 + b^2 = c^2, where c is the hypotenuse and a and b are the legs of the triangle.Given Values: We are given that one of the legs (a) is 15 cm and the hypotenuse (c) is 17 cm. We need to find the length of the other leg (b). We can rearrange the Pythagorean theorem to solve for b: b^2 = c^2 - a^2.Substitute Values: Substitute the given values into the equation: b^2 = 17^2 - 15^2. This simplifies to b^2 = 289 - 225.Calculate Difference: Calculate the difference: b^2 = 289 - 225 = 64.Find Square Root: Find the square root of b^2 to get the value of b: b = √64 = 8 cm.

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One of the legs of a right triangle measures
15cm and its hypotenuse measures
17cm. Find the measure of the other leg. If necessary, round to the nearest tenth.
Answer:
cm

One of the legs of a right triangle measures $15 \mathrm{~cm}$ and its hypotenuse measures $17 \mathrm{~cm}$ . Find the measure of the other leg. If necessary, round to the nearest tenth. $\newline$ Answer: $\square$ $\mathrm{cm}$

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Q. One of the legs of a right triangle measures

15 \mathrm{~cm}

and its hypotenuse measures

17 \mathrm{~cm}

. Find the measure of the other leg. If necessary, round to the nearest tenth.

\newline

Answer:

\square

\mathrm{cm}

Apply Pythagorean Theorem: To find the length of the other leg of the right triangle, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse $c$ is equal to the sum of the squares of the lengths of the other two sides $a$ and $b$ . The formula is $a^2 + b^2 = c^2$ , where $c$ is the hypotenuse and $a$ and $b$ are the legs of the triangle.
Given Values: We are given that one of the legs $a$ is $15$ cm and the hypotenuse $c$ is $17$ cm. We need to find the length of the other leg $b$ . We can rearrange the Pythagorean theorem to solve for $b$ : $b^2 = c^2 - a^2$ .
Substitute Values: Substitute the given values into the equation: $b^2 = 17^2 - 15^2$ . This simplifies to $b^2 = 289 - 225$ .
Calculate Difference: Calculate the difference: $b^2 = 289 - 225 = 64$ .
Find Square Root: Find the square root of $b^2$ to get the value of $b$ : $b = \sqrt{64} = 8\,\text{cm}$ .