Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

The River Rock Horse Rescue has a fenced-off pasture in the shape of a trapezoid. They need to calculate the area of the trapezoid to see how many horses it will safely hold. The bases of the trapezoid are 3030 meters long and 2020 meters long. The height of the trapezoid is 1010 meters.\newlineWhich equation can you use to find the area of the pasture, AA?\newlineChoices:\newline(A)A=12(20)(10+30)A = \frac{1}{2}(20)(10 + 30)\newline(B)A=12(10)(30+20)A = \frac{1}{2}(10)(30 + 20)\newlineWhat is the area of the pasture?\newlineWrite your answer as a whole number or decimal. Do not round.\newline____ square meters\newline

Full solution

Q. The River Rock Horse Rescue has a fenced-off pasture in the shape of a trapezoid. They need to calculate the area of the trapezoid to see how many horses it will safely hold. The bases of the trapezoid are 3030 meters long and 2020 meters long. The height of the trapezoid is 1010 meters.\newlineWhich equation can you use to find the area of the pasture, AA?\newlineChoices:\newline(A)A=12(20)(10+30)A = \frac{1}{2}(20)(10 + 30)\newline(B)A=12(10)(30+20)A = \frac{1}{2}(10)(30 + 20)\newlineWhat is the area of the pasture?\newlineWrite your answer as a whole number or decimal. Do not round.\newline____ square meters\newline
  1. Identify formula: Step 11: Identify the correct formula to calculate the area of a trapezoid.\newlineThe formula for the area of a trapezoid is A=12×(base1+base2)×heightA = \frac{1}{2} \times (\text{base}_1 + \text{base}_2) \times \text{height}. Comparing this with the given choices:\newline(A) A=12(20)(10+30)A = \frac{1}{2}(20)(10 + 30) - Incorrect, as it multiplies the wrong values.\newline(B) A=12(10)(30+20)A = \frac{1}{2}(10)(30 + 20) - Correct, as it uses the correct formula structure.
  2. Plug in values: Step 22: Plug in the values into the correct formula to calculate the area.\newlineUsing choice (B):\newlineA=12×(30+20)×10A = \frac{1}{2} \times (30 + 20) \times 10\newlineA=12×50×10A = \frac{1}{2} \times 50 \times 10\newlineA=250A = 250 square meters

More problems from Area of quadrilaterals and triangles: word problems