The rate of changedtdP of the number of algae in a test tube is modeled by a logistic differential equation. The maximum capacity of the tube is 580 algae. At 8AM, the number of algae in the test tube is 155 and is increasing at a rate of 31 algae per minute. Write a differential equation to describe the situation.dtdP=□
Q. The rate of change dtdP of the number of algae in a test tube is modeled by a logistic differential equation. The maximum capacity of the tube is 580 algae. At 8AM, the number of algae in the test tube is 155 and is increasing at a rate of 31 algae per minute. Write a differential equation to describe the situation.dtdP=□
Logistic Growth Model Equation: The logistic growth model is given by the differential equation:dtdP=rP(1−KP)where:- P is the population at time t,- r is the growth rate,- K is the carrying capacity of the environment (maximum population size).We need to find the value of r and use the given K value to write the differential equation.
Given Carrying Capacity: We are given the carrying capacity K as 580 algae. This value will be used in our differential equation.
Initial Algae Population Data: We are given that at 8AM, the number of algae is 155 and is increasing at a rate of 31 algae per minute. This rate of increase is the value of (dP)/(dt) when P=155.
Calculate Growth Rate: To find the growth rate r, we can use the given rate of change when P=155. Plugging these values into the logistic growth model, we get:31=r×155×(1−155/580)Now we need to solve for r.
Simplify Fraction: First, simplify the fraction inside the parentheses: 1−580155=1−0.26724≈0.73276
Solve for Growth Rate: Now, plug this value back into the equation and solve for r:31=r×155×0.73276r≈31/(155×0.73276)r≈31/113.5778r≈0.273
Write Differential Equation: Now that we have the value of r, we can write the logistic differential equation as:dtdP=0.273P(1−580P)This equation models the rate of change of the number of algae in the test tube.
More problems from Evaluate two-variable equations: word problems