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The population of a city increases by 
1.5% per year. If this year's population is 268,000 , what will next year's population be, to the nearest individual?
Answer:

The population of a city increases by 1.5% 1.5 \% per year. If this year's population is 268268,000000 , what will next year's population be, to the nearest individual?\newlineAnswer:

Full solution

Q. The population of a city increases by 1.5% 1.5 \% per year. If this year's population is 268268,000000 , what will next year's population be, to the nearest individual?\newlineAnswer:
  1. Convert to Decimal: Determine the percentage increase in decimal form.\newlineTo convert a percentage to a decimal, divide by 100100.\newline1.5%=1.5100=0.0151.5\% = \frac{1.5}{100} = 0.015
  2. Calculate Increase: Calculate the increase in population.\newlineTo find the increase, multiply the current population by the decimal form of the percentage increase.\newlineIncrease =268,000×0.015= 268,000 \times 0.015
  3. Calculate Increase: Perform the calculation for the increase.\newlineIncrease = 268,000×0.015=4,020268,000 \times 0.015 = 4,020
  4. Calculate Next Year's Population: Calculate next year's population. To find next year's population, add the increase to the current population. Next year's population = Current population + Increase Next year's population = 268,000+4,020268,000 + 4,020
  5. Perform Calculation: Perform the calculation for next year's population.\newlineNext year's population = 268,000+4,020=272,020268,000 + 4,020 = 272,020

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