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On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming these flowers rapidly increases as the trees blossom. The locust population gains 
87% of its size every 2.4 days, and can be modeled by a function, 
L, which depends on the amount of time, 
t (in days).
Before the first day of spring, there were 1100 locusts in the population.
Write a function that models the locust population 
t days since the first day of spring.

L(t)=

On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming these flowers rapidly increases as the trees blossom. The locust population gains 87% 87 \% of its size every 22.44 days, and can be modeled by a function, L L , which depends on the amount of time, t t (in days).\newlineBefore the first day of spring, there were 11001100 locusts in the population.\newlineWrite a function that models the locust population t t days since the first day of spring.\newlineL(t)= L(t)=

Full solution

Q. On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming these flowers rapidly increases as the trees blossom. The locust population gains 87% 87 \% of its size every 22.44 days, and can be modeled by a function, L L , which depends on the amount of time, t t (in days).\newlineBefore the first day of spring, there were 11001100 locusts in the population.\newlineWrite a function that models the locust population t t days since the first day of spring.\newlineL(t)= L(t)=
  1. Identify values: Identify the initial value aa and the growth rate rr. The initial value, aa, is the starting population of locusts, which is 11001100. The growth rate, rr, is 8787\%, which can be expressed as a decimal 0.870.87.
  2. Determine growth factor: Determine the growth factor bb. Since the population increases by 87%87\%, the growth factor bb is 11 plus the growth rate. b=1+rb = 1 + r b=1+0.87b = 1 + 0.87 b=1.87b = 1.87
  3. Determine time period: Determine the time period for the growth rate.\newlineThe problem states that the population gains 87%87\% every 2.42.4 days. Therefore, the growth factor applies every 2.42.4 days.
  4. Write exponential function: Write the exponential function.\newlineThe exponential function for growth is L(t)=a(b)(t/k)L(t) = a(b)^{(t/k)}, where kk is the time period for each growth cycle.\newlineIn this case, k=2.4k = 2.4 days.\newlineSo, the function becomes L(t)=1100(1.87)(t/2.4)L(t) = 1100(1.87)^{(t/2.4)}.

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