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The perimeter of an airplane ticket is 3434 centimeters. The area is 7070 square centimeters. What are the dimensions of the ticket?\newline___\_\_\_ centimeters by ___\_\_\_ centimeters

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Q. The perimeter of an airplane ticket is 3434 centimeters. The area is 7070 square centimeters. What are the dimensions of the ticket?\newline___\_\_\_ centimeters by ___\_\_\_ centimeters
  1. Define Variables: Let ll be the length and ww be the width of the airplane ticket.\newlineThe perimeter (P)(P) of a rectangle is given by the formula P=2l+2wP = 2l + 2w.
  2. Perimeter Equation: Given the perimeter of the airplane ticket is 3434 centimeters, we can write the equation 34=2l+2w34 = 2l + 2w.
  3. Simplify Perimeter: Simplify the perimeter equation by dividing all terms by 22 to get 17=l+w17 = l + w.
  4. Area Equation: The area AA of a rectangle is given by the formula A=lwA = lw. Given the area of the airplane ticket is 7070 square centimeters, we can write the equation 70=lw70 = lw.
  5. Solve System of Equations: We now have a system of two equations with two variables:\newline11. 17=l+w17 = l + w\newline22. 70=lw70 = lw\newlineWe can solve this system by expressing one variable in terms of the other using the first equation and then substituting into the second equation.
  6. Express ww in terms of ll: From the first equation, express ww in terms of ll: w=17lw = 17 - l.
  7. Substitute into Area Equation: Substitute w=17lw = 17 - l into the second equation 70=lw70 = lw to get 70=l(17l)70 = l(17 - l).
  8. Expand Quadratic Equation: Expand the equation 70=17ll270 = 17l - l^2 to form a quadratic equation 0=l217l+700 = l^2 - 17l + 70.
  9. Factor Quadratic Equation: Factor the quadratic equation l217l+70=0l^2 - 17l + 70 = 0 to find the values of ll. The factors of 7070 that add up to 1717 are 1010 and 77, so the factored form is (l10)(l7)=0(l - 10)(l - 7) = 0.
  10. Solve for ll: Solve for ll by setting each factor equal to zero: l10=0l - 10 = 0 or l7=0l - 7 = 0. This gives us two possible values for ll: l=10l = 10 or l=7l = 7.
  11. Find Possible Dimensions: If l=10l = 10, then w=17l=1710=7w = 17 - l = 17 - 10 = 7. If l=7l = 7, then w=17l=177=10w = 17 - l = 17 - 7 = 10. Since a rectangle's length and width are interchangeable, the dimensions of the ticket can be 1010 centimeters by 77 centimeters or 77 centimeters by 1010 centimeters.

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