The perimeter of an airplane ticket is 34 centimeters. The area is 70 square centimeters. What are the dimensions of the ticket?___ centimeters by ___ centimeters
Q. The perimeter of an airplane ticket is 34 centimeters. The area is 70 square centimeters. What are the dimensions of the ticket?___ centimeters by ___ centimeters
Define Variables: Let l be the length and w be the width of the airplane ticket.The perimeter (P) of a rectangle is given by the formula P=2l+2w.
Perimeter Equation: Given the perimeter of the airplane ticket is 34 centimeters, we can write the equation 34=2l+2w.
Simplify Perimeter: Simplify the perimeter equation by dividing all terms by 2 to get 17=l+w.
Area Equation: The area A of a rectangle is given by the formula A=lw. Given the area of the airplane ticket is 70 square centimeters, we can write the equation 70=lw.
Solve System of Equations: We now have a system of two equations with two variables:1. 17=l+w2. 70=lwWe can solve this system by expressing one variable in terms of the other using the first equation and then substituting into the second equation.
Express w in terms of l: From the first equation, express w in terms of l: w=17−l.
Substitute into Area Equation: Substitute w=17−l into the second equation 70=lw to get 70=l(17−l).
Expand Quadratic Equation: Expand the equation 70=17l−l2 to form a quadratic equation0=l2−17l+70.
Factor Quadratic Equation: Factor the quadratic equation l2−17l+70=0 to find the values of l. The factors of 70 that add up to 17 are 10 and 7, so the factored form is (l−10)(l−7)=0.
Solve for l: Solve for l by setting each factor equal to zero: l−10=0 or l−7=0. This gives us two possible values for l: l=10 or l=7.
Find Possible Dimensions: If l=10, then w=17−l=17−10=7. If l=7, then w=17−l=17−7=10. Since a rectangle's length and width are interchangeable, the dimensions of the ticket can be 10 centimeters by 7 centimeters or 7 centimeters by 10 centimeters.
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