The perimeter of a rectangular dining room is 22 meters. The area is 24 square meters. What are the dimensions of the dining room?___ meters by ___ meters
Q. The perimeter of a rectangular dining room is 22 meters. The area is 24 square meters. What are the dimensions of the dining room?___ meters by ___ meters
Define Variables: Let's denote the length of the dining room as l meters and the width as w meters. The perimeter (P) of a rectangle is given by the formula P=2l+2w. Since we know the perimeter is 22 meters, we can write the equation:22=2l+2w
Perimeter Equation: We can simplify the equation by dividing both sides by 2 to find the sum of the length and width:11=l+w
Simplify Perimeter Equation: The area A of a rectangle is given by the formula A=l×w. We know the area is 24 square meters, so we can write the equation: 24=l×w
Area Equation: Now we have a system of two equations with two variables:1. 11=l+w2. 24=l×wWe can solve this system by expressing one variable in terms of the other using the first equation and then substituting it into the second equation. Let's express w in terms of l:w=11−l
Solve System of Equations: Substitute w from the previous step into the area equation:24=l×(11−l)This gives us a quadratic equation:24=11l−l2Rearranging the terms to set the equation to zero:l2−11l+24=0
Express Width in Terms of Length: We can factor the quadratic equation:(l−8)(l−3)=0This gives us two possible solutions for l:l=8 or l=3
Substitute Width into Area Equation: If l=8, then substituting back into w=11−l gives us:w=11−8w=3And if l=3, then:w=11−3w=8So the dimensions of the dining room can be either 8 meters by 3 meters or 3 meters by 8 meters since a rectangle's length and width are interchangeable.
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