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The perimeter of a rectangular dining room is 2222 meters. The area is 2424 square meters. What are the dimensions of the dining room?\newline___\_\_\_ meters by ___\_\_\_ meters

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Q. The perimeter of a rectangular dining room is 2222 meters. The area is 2424 square meters. What are the dimensions of the dining room?\newline___\_\_\_ meters by ___\_\_\_ meters
  1. Define Variables: Let's denote the length of the dining room as ll meters and the width as ww meters. The perimeter (P)(P) of a rectangle is given by the formula P=2l+2wP = 2l + 2w. Since we know the perimeter is 2222 meters, we can write the equation:\newline22=2l+2w22 = 2l + 2w
  2. Perimeter Equation: We can simplify the equation by dividing both sides by 22 to find the sum of the length and width:\newline11=l+w11 = l + w
  3. Simplify Perimeter Equation: The area AA of a rectangle is given by the formula A=l×wA = l \times w. We know the area is 2424 square meters, so we can write the equation: 24=l×w24 = l \times w
  4. Area Equation: Now we have a system of two equations with two variables:\newline11. 11=l+w11 = l + w\newline22. 24=l×w24 = l \times w\newlineWe can solve this system by expressing one variable in terms of the other using the first equation and then substituting it into the second equation. Let's express ww in terms of ll:\newlinew=11lw = 11 - l
  5. Solve System of Equations: Substitute ww from the previous step into the area equation:\newline24=l×(11l)24 = l \times (11 - l)\newlineThis gives us a quadratic equation:\newline24=11ll224 = 11l - l^2\newlineRearranging the terms to set the equation to zero:\newlinel211l+24=0l^2 - 11l + 24 = 0
  6. Express Width in Terms of Length: We can factor the quadratic equation:\newline(l8)(l3)=0(l - 8)(l - 3) = 0\newlineThis gives us two possible solutions for ll:\newlinel=8l = 8 or l=3l = 3
  7. Substitute Width into Area Equation: If l=8l = 8, then substituting back into w=11lw = 11 - l gives us:\newlinew=118w = 11 - 8\newlinew=3w = 3\newlineAnd if l=3l = 3, then:\newlinew=113w = 11 - 3\newlinew=8w = 8\newlineSo the dimensions of the dining room can be either 88 meters by 33 meters or 33 meters by 88 meters since a rectangle's length and width are interchangeable.

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