The perimeter of a playing card is 30 centimeters. The area is 54 square centimeters. What are the dimensions of the playing card?___ centimeters by ___ centimeters
Q. The perimeter of a playing card is 30 centimeters. The area is 54 square centimeters. What are the dimensions of the playing card?___ centimeters by ___ centimeters
Define Card Dimensions: Let the length of the playing card be l centimeters and the width be w centimeters.The perimeter of a rectangle is given by the formula P=2l+2w.
Perimeter Equation: Given the perimeter of the playing card is 30 centimeters, we can write the equation:30=2l+2w
Simplify Perimeter: Simplify the perimeter equation by dividing all terms by 2 to make it easier to work with:15=l+w
Area Calculation: The area of a rectangle is given by the formula A=lw.Given the area of the playing card is 54 square centimeters, we can write the equation:54=lw
System of Equations: We now have a system of two equations with two variables:15=l+w (Equation 1)54=lw (Equation 2)We can solve this system by expressing one variable in terms of the other using Equation 1 and then substituting into Equation 2.
Express Width in Terms of Length: From Equation 1, express w in terms of l:w=15−l
Substitute Width into Area Equation: Substitute w=15−l into Equation 2:54=l(15−l)
Expand and Rearrange Equation: Expand the equation and rearrange it into a quadratic equation:54=15l−l20=l2−15l+54
Factor Quadratic Equation: Factor the quadratic equation: 0=(l−9)(l−6)
Solve for Length: Solve for l by setting each factor equal to zero:l−9=0 or l−6=0l=9 or l=6
Find Possible Solutions: Since l and w are interchangeable in a rectangle (it doesn't matter which one is length and which one is width), we can have two solutions:If l=9, then w=15−9=6.If l=6, then w=15−6=9.
Check Validity of Solutions: Check the solutions by verifying that they satisfy both the perimeter and area equations:For l=9 and w=6:Perimeter check: 2l+2w=2(9)+2(6)=18+12=30 (matches given perimeter)Area check: lw=9×6=54 (matches given area)
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