The number y is irrational. is the base of the natural logarithm. Which statement about y - is true? Choices: (A)y - is rational. (B)y - is irrational. (C)y - can be rational or irrational, depending on the value of y.

Identify Type of e: Identify whether e is a rational or irrational number. e is the base of the natural logarithm and is known to be an irrational number.Properties of Irrational Numbers: Consider the properties of irrational numbers. The difference between two irrational numbers can be either rational or irrational. It depends on the specific values of the numbers.Analyze y - e: Analyze the possible outcomes for y - e. If y = e, then y - e = e - e = 0, which is rational. If y is any irrational number different from e, then y - e is not guaranteed to be rational; it could be irrational. Therefore, y - e can be rational or irrational, depending on the value of y.

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The number $y$ is irrational. $e$ is the base of the natural logarithm. Which statement about $y - e$ is true? $\newline$ Choices: $\newline$ (A) $y - e$ is rational. $\newline$ (B) $y - e$ is irrational. $\newline$ (C) $y - e$ can be rational or irrational, depending on the value of $y$ .

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Math Problems

Algebra 2

Properties of operations on rational and irrational numbers

Full solution

Q. The number

y

is irrational.

e

is the base of the natural logarithm. Which statement about

y - e

is true?

\newline

Choices:

\newline

(A)

y - e

is rational.

\newline

(B)

y - e

is irrational.

\newline

(C)

y - e

can be rational or irrational, depending on the value of

y

Identify Type of $e$ : Identify whether $e$ is a rational or irrational number. $\newline$ $e$ is the base of the natural logarithm and is known to be an irrational number.
Properties of Irrational Numbers: Consider the properties of irrational numbers. The difference between two irrational numbers can be either rational or irrational. It depends on the specific values of the numbers.
Analyze $y - e$ : Analyze the possible outcomes for $y - e$ . $\newline$ If $y = e$ , then $y - e = e - e = 0$ , which is rational. $\newline$ If $y$ is any irrational number different from $e$ , then $y - e$ is not guaranteed to be rational; it could be irrational. $\newline$ Therefore, $y - e$ can be rational or irrational, depending on the value of $y$ .