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The number of people waiting in line to buy a new piece of technology is measured by the differentiable function 
f, where 
f(t) is measured in people and 
t is measured in hours after the store opened. What are the units of 
(1)/(2)int_(3)^(5)f(t)dt ?
people
hours
people / hour
hours / person
people / hour 
^(2)
hours / person 
^(2)

The number of people waiting in line to buy a new piece of technology is measured by the differentiable function f f , where f(t) f(t) is measured in people and t t is measured in hours after the store opened. What are the units of 1235f(t)dt \frac{1}{2} \int_{3}^{5} f(t) d t ?\newlinepeople\newlinehours\newlinepeople / hour\newlinehours / person\newlinepeople / hour 2 { }^{2} \newlinehours / person 2 { }^{2}

Full solution

Q. The number of people waiting in line to buy a new piece of technology is measured by the differentiable function f f , where f(t) f(t) is measured in people and t t is measured in hours after the store opened. What are the units of 1235f(t)dt \frac{1}{2} \int_{3}^{5} f(t) d t ?\newlinepeople\newlinehours\newlinepeople / hour\newlinehours / person\newlinepeople / hour 2 { }^{2} \newlinehours / person 2 { }^{2}
  1. Understand Integral Units: Understand the integral and its units.\newlineThe integral 35f(t)dt\int_{3}^{5}f(t)\,dt represents the total number of people who have waited in line from hour 33 to hour 55 after the store opened. Since f(t)f(t) is measured in people and tt is measured in hours, the integral itself has units of people multiplied by hours (people*hours).
  2. Consider Factor Effect: Consider the factor (1)/(2)(1)/(2) and its effect on units. Multiplying the integral by (1)/(2)(1)/(2) does not change the units. It simply halves the value of the integral. Therefore, the units remain people*hours.
  3. Determine Expression Units: Determine the units of the expression.\newlineSince the integral has units of people*hours, and we have not changed the units by multiplying by (1)/(2)(1)/(2), the units of the entire expression (1)/(2)(3)(5)f(t)dt(1)/(2)\int_{(3)}^{(5)}f(t)\,dt are still people*hours.

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