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The following data points represent the yearly salaries of high school cheerleading coaches in Dakota County (in thousands of dollars).

41,38,36,57,43
Find the mean absolute deviation (MAD) of the data set.
thousand dollars

The following data points represent the yearly salaries of high school cheerleading coaches in Dakota County (in thousands of dollars). $\newline$ $41,38,36,57,43$ $\newline$ Find the mean absolute deviation (MAD) of the data set. $\newline$ thousand dollars

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Q. The following data points represent the yearly salaries of high school cheerleading coaches in Dakota County (in thousands of dollars).

\newline

41,38,36,57,43

\newline

Find the mean absolute deviation (MAD) of the data set.

\newline

thousand dollars

Calculate Mean: List the data points and calculate the mean (average) of the data set. $\newline$ Data points: $41, 38, 36, 57, 43$ (in thousands of dollars) $\newline$ Mean = (Sum of all data points) / (Number of data points) $\newline$ Mean = $(41 + 38 + 36 + 57 + 43) / 5$ $\newline$ Mean = $215 / 5$ $\newline$ Mean = $43$
Calculate Absolute Deviations: Calculate the absolute deviations from the mean for each data point. $\newline$ Absolute deviation for each data point = $|\text{Data point} - \text{Mean}|$ $\newline$ Absolute deviations: $\newline$ $|41 - 43| = 2$ $\newline$ $|38 - 43| = 5$ $\newline$ $|36 - 43| = 7$ $\newline$ $|57 - 43| = 14$ $\newline$ $|43 - 43| = 0$
Calculate Mean Absolute Deviation: Calculate the mean of the absolute deviations. $\newline$ Mean Absolute Deviation (MAD) = $(\text{Sum of absolute deviations}) / (\text{Number of data points})$ $\newline$ MAD = $(2 + 5 + 7 + 14 + 0) / 5$ $\newline$ MAD = $28 / 5$ $\newline$ MAD = $5.6$

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