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The focal length, FF, of a camera's lens is related to the distance of the object from the lens. II and the distance to the image area in the camera, WW, by the formula below.\newline1J+1W=1F\frac{1}{J}+\frac{1}{W}=\frac{1}{F}\newlineWhen this equation is solved for JJ in terms of FF and WW. JJ equals\newline(1)(1)(FW)(F-W)\newline(2)(2) FWF+W\frac{FW}{F+W}\newline(3)(3) FWFW\frac{FW}{F-W}\newline(4)(4) 1F\frac{1}{F}-1W\frac{1}{W}

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Q. The focal length, FF, of a camera's lens is related to the distance of the object from the lens. II and the distance to the image area in the camera, WW, by the formula below.\newline1J+1W=1F\frac{1}{J}+\frac{1}{W}=\frac{1}{F}\newlineWhen this equation is solved for JJ in terms of FF and WW. JJ equals\newline(1)(1)(FW)(F-W)\newline(2)(2) FWF+W\frac{FW}{F+W}\newline(3)(3) FWFW\frac{FW}{F-W}\newline(4)(4) 1F\frac{1}{F}-1W\frac{1}{W}
  1. Write Equation: Write down the given equation.\newlineWe have the equation (1J)+(1W)=(1F)(\frac{1}{J}) + (\frac{1}{W}) = (\frac{1}{F}).
  2. Isolate J: Get terms involving J on one side of the equation.\newlineTo isolate J, we subtract (1W)(\frac{1}{W}) from both sides of the equation to get (1J)=(1F)(1W)(\frac{1}{J}) = (\frac{1}{F}) - (\frac{1}{W}).
  3. Find Common Denominator: Find a common denominator for the right side of the equation.\newlineThe common denominator for FF and WW is FWF\ast W. So we rewrite the right side as (WFW)(FFW)\left(\frac{W}{F\ast W}\right) - \left(\frac{F}{F\ast W}\right).
  4. Combine Fractions: Combine the fractions on the right side of the equation. After finding the common denominator, we combine the fractions to get (1J)=WFFW(\frac{1}{J}) = \frac{W - F}{F\ast W}.
  5. Invert to Solve for J: Invert both sides of the equation to solve for J. We take the reciprocal of both sides to get J=FWWFJ = \frac{F \cdot W}{W - F}.

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