The equation of a parabola is y=x2+8x+18. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Q. The equation of a parabola is y=x2+8x+18. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Identify vertex form: Identify the vertex form of a parabola.The vertex form of a parabola is given by the equation y=a(x−h)2+k, where (h,k) is the vertex of the parabola.
Complete the square:Complete the square to rewrite the given equation in vertex form.The given equation is y=x2+8x+18. To complete the square, we need to find a value that, when added and subtracted to the equation, forms a perfect square trinomial with the x-terms.
Calculate value: Calculate the value needed to complete the square.We take half of the coefficient of the x-term, which is 8, and square it to get (28)2=42=16. This is the value we will add and subtract to complete the square.
Rewrite equation: Rewrite the equation by adding and subtracting the value found in Step 3.y=x2+8x+16+18−16y=(x2+8x+16)+2Now, the equation includes the perfect square trinomial (x2+8x+16) and the constant 2.
Factor and simplify: Factor the perfect square trinomial and simplify the equation.y=(x+4)2+2This is the vertex form of the given parabola, where the vertex is (−4,2).
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