The equation of a parabola is y=x2+6x+19. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Q. The equation of a parabola is y=x2+6x+19. Write the equation in vertex form.Write any numbers as integers or simplified proper or improper fractions.______
Identify vertex form: Identify the vertex form of a parabola.The vertex form of a parabola is given by y=a(x−h)2+k, where (h,k) is the vertex of the parabola.
Complete the square:Complete the square to rewrite the given equation in vertex form.The given equation is y=x2+6x+19. To complete the square, we need to find a value that, when added and subtracted to the equation, forms a perfect square trinomial.
Calculate value: Calculate the value needed to complete the square.We take the coefficient of the x term, which is 6, divide it by 2, and then square it to get the value to add and subtract.(26)2=32=9
Add and subtract: Add and subtract the calculated value inside the equation.y=x2+6x+9+19−9y=(x2+6x+9)+10Now, the equation has a perfect square trinomial and a constant term 10.
Factor and simplify: Factor the perfect square trinomial and simplify the equation.y=(x+3)2+10This is the equation in vertex form, where the vertex is (−3,10).
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